Wednesday 11 January 2012

What is wrong?


Question 2
Describe what's wrong with the working and/or answer.
Suggest how it should look like.

14 comments:

  1. Transfer error: 1/4 m^2 becomes1/2 m^2

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  2. 1/4m^2 is not equal to 1/2m X1/2m as the square is only for m.

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  3. This comment has been removed by the author.

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  4. 1/4m^2= (1/4m)(1/4m)=1/16m^2

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  5. 1/4m^2 is not equal to (1/2m)^2 as the increase in power is only for the m and not the 1/2.

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  6. he did not factorize it correctly for (9/16n)(9/16n) as there is 9/16n^2 , he had forgotten to square root 9/16, thus it should be 3/4. therefore,
    (14) 1/4m^2 - 9/16n^2
    = (1/2m)(1/2m) - (3/4n)(3/4n)
    = (1/2m + 3/4n)(1/2m - 3/4n)

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  7. 1/4m^2 - 9/16n^2
    =(1/2m)(1/2m)-(3/4n)(3/4n)
    =(1/2m+3/4n)(1/2m-3/4n) #

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  8. The 2nd part is wrong it should be

    =(0.5m)(0.5m) - (3/4n)(3/4n)

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  9. (9/16n)x(9/16n) is not 9/16n^2

    And therefore the answer should be m^2/4-9n^2/16

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  10. (9/16n)(9/16n) is not equal to 9/16n^2 so it should be (3/4n)(3/4n) and the answer should be (1/2m+3/4n)(1/2m-3/4n). I think is a careless mistake as he had done it correctly for 1/4m^2 which basically had the same concept as the 9/16n^2.

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  11. Transfer ERROR

    -9/16n^2 doesn't equal to -(9/16n)(9/16n)


    -9/16n^2 equals to -(3/4n)(3/4n)

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  12. -9/16n^2 does not equal to -(9/16n)(9/16n)
    -9/16n^2should be equal to -(3/4n)(3/4n) because it has to be factorised too.

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  13. Transfer error.

    -9/16n^2 is not equal to -(9/16n)(9/16n)
    -9/16n^2 is equal to -(3/4n)(3/4n)

    ReplyDelete